3(2z+25)=78+2z-2

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Solution for 3(2z+25)=78+2z-2 equation:



3(2z+25)=78+2z-2
We move all terms to the left:
3(2z+25)-(78+2z-2)=0
We add all the numbers together, and all the variables
3(2z+25)-(2z+76)=0
We multiply parentheses
6z-(2z+76)+75=0
We get rid of parentheses
6z-2z-76+75=0
We add all the numbers together, and all the variables
4z-1=0
We move all terms containing z to the left, all other terms to the right
4z=1
z=1/4
z=1/4

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