3(2z+25)=78+2z-2

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Solution for 3(2z+25)=78+2z-2 equation: 



3(2z+25)=78+2z-2

We move all terms to the left:

3(2z+25)-(78+2z-2)=0

We add all the numbers together, and all the variables

3(2z+25)-(2z+76)=0

We multiply parentheses

6z-(2z+76)+75=0

We get rid of parentheses

6z-2z-76+75=0

We add all the numbers together, and all the variables

4z-1=0

We move all terms containing z to the left, all other terms to the right

4z=1

z=1/4

z=1/4

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