3(2z+4)=30z+12

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Solution for 3(2z+4)=30z+12 equation: 



3(2z+4)=30z+12

We move all terms to the left:

3(2z+4)-(30z+12)=0

We multiply parentheses

6z-(30z+12)+12=0

We get rid of parentheses

6z-30z-12+12=0

We add all the numbers together, and all the variables

-24z=0

z=0/-24

z=0

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