3(2z+5)=3z+36

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Solution for 3(2z+5)=3z+36 equation: 



3(2z+5)=3z+36

We move all terms to the left:

3(2z+5)-(3z+36)=0

We multiply parentheses

6z-(3z+36)+15=0

We get rid of parentheses

6z-3z-36+15=0

We add all the numbers together, and all the variables

3z-21=0

We move all terms containing z to the left, all other terms to the right

3z=21

z=21/3

z=7

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