3(2z+5)=3z/4+36

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Solution for 3(2z+5)=3z/4+36 equation: 


z in (-oo:+oo)

3*(2*z+5) = (3*z)/4+36 // - (3*z)/4+36

3*(2*z+5)-((3*z)/4)-36 = 0

3*(2*z+5)+(-3/4)*z-36 = 0

3*(2*z+5)+(-3*z)/4-36 = 0

(3*4*(2*z+5))/4+(-3*z)/4+(-36*4)/4 = 0

3*4*(2*z+5)-3*z-36*4 = 0

21*z-144+60 = 0

21*z-84 = 0

(21*z-84)/4 = 0

(21*z-84)/4 = 0 // * 4

21*z-84 = 0

21*z-84 = 0 // + 84

21*z = 84 // : 21

z = 84/21

z = 4

z = 4

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