3(2z+6)+4=5(z-3)

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Solution for 3(2z+6)+4=5(z-3) equation: 



3(2z+6)+4=5(z-3)

We move all terms to the left:

3(2z+6)+4-(5(z-3))=0

We multiply parentheses

6z-(5(z-3))+18+4=0



We calculate terms in parentheses: -(5(z-3)), so:

5(z-3)

We multiply parentheses

5z-15

Back to the equation:

-(5z-15)



We add all the numbers together, and all the variables

6z-(5z-15)+22=0

We get rid of parentheses

6z-5z+15+22=0

We add all the numbers together, and all the variables

z+37=0

We move all terms containing z to the left, all other terms to the right

z=-37

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