3(2z+8)=2(z-1)+18

Solution for 3(2z+8)=2(z-1)+18 equation:

3(2z+8)=2(z-1)+18

We move all terms to the left:

3(2z+8)-(2(z-1)+18)=0

We multiply parentheses

6z-(2(z-1)+18)+24=0


We calculate terms in parentheses: -(2(z-1)+18), so:

2(z-1)+18

We multiply parentheses

2z-2+18

We add all the numbers together, and all the variables

2z+16

Back to the equation:

-(2z+16)


We get rid of parentheses

6z-2z-16+24=0

We add all the numbers together, and all the variables

4z+8=0

We move all terms containing z to the left, all other terms to the right

4z=-8

z=-8/4

z=-2