3(2z-1)-2(2+9)=z(z+)

Solution for 3(2z-1)-2(2+9)=z(z+) equation:

3(2z-1)-2(2+9)=z(z+)

We move all terms to the left:

3(2z-1)-2(2+9)-(z(z+))=0

We add all the numbers together, and all the variables

3(2z-1)-(z(+z))-211=0

We multiply parentheses

6z-(z(+z))-3-211=0


We calculate terms in parentheses: -(z(+z)), so:

z(+z)

We multiply parentheses

z^2

Back to the equation:

-(z^2)


determiningTheFunctionDomain
-z^2+6z-3-211=0

We add all the numbers together, and all the variables

-1z^2+6z-214=0

a = -1; b = 6; c = -214;
Δ = b2-4ac
Δ = 62-4·(-1)·(-214)
Δ = -820
Delta is less than zero, so there is no solution for the equation