3(2z-1)-2(2z+4)=2(z+1)

Solution for 3(2z-1)-2(2z+4)=2(z+1) equation:

Simplifying
3(2z + -1) + -2(2z + 4) = 2(z + 1)

Reorder the terms:
3(-1 + 2z) + -2(2z + 4) = 2(z + 1)
(-1 * 3 + 2z * 3) + -2(2z + 4) = 2(z + 1)
(-3 + 6z) + -2(2z + 4) = 2(z + 1)

Reorder the terms:
-3 + 6z + -2(4 + 2z) = 2(z + 1)
-3 + 6z + (4 * -2 + 2z * -2) = 2(z + 1)
-3 + 6z + (-8 + -4z) = 2(z + 1)

Reorder the terms:
-3 + -8 + 6z + -4z = 2(z + 1)

Combine like terms: -3 + -8 = -11
-11 + 6z + -4z = 2(z + 1)

Combine like terms: 6z + -4z = 2z
-11 + 2z = 2(z + 1)

Reorder the terms:
-11 + 2z = 2(1 + z)
-11 + 2z = (1 * 2 + z * 2)
-11 + 2z = (2 + 2z)

Add '-2z' to each side of the equation.
-11 + 2z + -2z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-11 + 0 = 2 + 2z + -2z
-11 = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-11 = 2 + 0
-11 = 2

Solving
-11 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.