3(2z-1)-2(z+9)=z(z+1)

Solution for 3(2z-1)-2(z+9)=z(z+1) equation:

3(2z-1)-2(z+9)=z(z+1)

We move all terms to the left:

3(2z-1)-2(z+9)-(z(z+1))=0

We multiply parentheses

6z-2z-(z(z+1))-3-18=0


We calculate terms in parentheses: -(z(z+1)), so:

z(z+1)

We multiply parentheses

z^2+z

Back to the equation:

-(z^2+z)


We add all the numbers together, and all the variables

4z-(z^2+z)-21=0

We get rid of parentheses

-z^2+4z-z-21=0

We add all the numbers together, and all the variables

-1z^2+3z-21=0

a = -1; b = 3; c = -21;
Δ = b2-4ac
Δ = 32-4·(-1)·(-21)
Δ = -75
Delta is less than zero, so there is no solution for the equation