3(2z-3)=5(z+2)

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Solution for 3(2z-3)=5(z+2) equation:


Simplifying
3(2z + -3) = 5(z + 2)

Reorder the terms:
3(-3 + 2z) = 5(z + 2)
(-3 * 3 + 2z * 3) = 5(z + 2)
(-9 + 6z) = 5(z + 2)

Reorder the terms:
-9 + 6z = 5(2 + z)
-9 + 6z = (2 * 5 + z * 5)
-9 + 6z = (10 + 5z)

Solving
-9 + 6z = 10 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-9 + 6z + -5z = 10 + 5z + -5z

Combine like terms: 6z + -5z = 1z
-9 + 1z = 10 + 5z + -5z

Combine like terms: 5z + -5z = 0
-9 + 1z = 10 + 0
-9 + 1z = 10

Add '9' to each side of the equation.
-9 + 9 + 1z = 10 + 9

Combine like terms: -9 + 9 = 0
0 + 1z = 10 + 9
1z = 10 + 9

Combine like terms: 10 + 9 = 19
1z = 19

Divide each side by '1'.
z = 19

Simplifying
z = 19

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