3(2z-3)=5(z+3)+z

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Solution for 3(2z-3)=5(z+3)+z equation: 


Simplifying
3(2z + -3) = 5(z + 3) + z

Reorder the terms:
3(-3 + 2z) = 5(z + 3) + z
(-3 * 3 + 2z * 3) = 5(z + 3) + z
(-9 + 6z) = 5(z + 3) + z

Reorder the terms:
-9 + 6z = 5(3 + z) + z
-9 + 6z = (3 * 5 + z * 5) + z
-9 + 6z = (15 + 5z) + z

Combine like terms: 5z + z = 6z
-9 + 6z = 15 + 6z

Add '-6z' to each side of the equation.
-9 + 6z + -6z = 15 + 6z + -6z

Combine like terms: 6z + -6z = 0
-9 + 0 = 15 + 6z + -6z
-9 = 15 + 6z + -6z

Combine like terms: 6z + -6z = 0
-9 = 15 + 0
-9 = 15

Solving
-9 = 15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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