3(2z-3)=6z-(3z-11)-2

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Solution for 3(2z-3)=6z-(3z-11)-2 equation: 



3(2z-3)=6z-(3z-11)-2

We move all terms to the left:

3(2z-3)-(6z-(3z-11)-2)=0

We multiply parentheses

6z-(6z-(3z-11)-2)-9=0



We calculate terms in parentheses: -(6z-(3z-11)-2), so:

6z-(3z-11)-2

We get rid of parentheses

6z-3z+11-2

We add all the numbers together, and all the variables

3z+9

Back to the equation:

-(3z+9)



We get rid of parentheses

6z-3z-9-9=0

We add all the numbers together, and all the variables

3z-18=0

We move all terms containing z to the left, all other terms to the right

3z=18

z=18/3

z=6

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