3(2z-4)-10z=16

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Solution for 3(2z-4)-10z=16 equation: 



3(2z-4)-10z=16

We move all terms to the left:

3(2z-4)-10z-(16)=0

We add all the numbers together, and all the variables

-10z+3(2z-4)-16=0

We multiply parentheses

-10z+6z-12-16=0

We add all the numbers together, and all the variables

-4z-28=0

We move all terms containing z to the left, all other terms to the right

-4z=28

z=28/-4

z=-7

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