3(2z-4)/7=2z-12

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Solution for 3(2z-4)/7=2z-12 equation: 


z in (-oo:+oo)

(3*(2*z-4))/7 = 2*z-12 // - 2*z-12

(3*(2*z-4))/7-(2*z)+12 = 0

(3*(2*z-4))/7-2*z+12 = 0

(3*(2*z-4))/7+(-2*7*z)/7+(7*12)/7 = 0

3*(2*z-4)-2*7*z+7*12 = 0

84-8*z-12 = 0

72-8*z = 0

(72-8*z)/7 = 0

(72-8*z)/7 = 0 // * 7

72-8*z = 0

72-8*z = 0 // - 72

-8*z = -72 // : -8

z = -72/(-8)

z = 9

z = 9

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