3(2z-4)/7=2z-5

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Solution for 3(2z-4)/7=2z-5 equation: 


z in (-oo:+oo)

(3*(2*z-4))/7 = 2*z-5 // - 2*z-5

(3*(2*z-4))/7-(2*z)+5 = 0

(3*(2*z-4))/7-2*z+5 = 0

(3*(2*z-4))/7+(-2*7*z)/7+(5*7)/7 = 0

3*(2*z-4)-2*7*z+5*7 = 0

35-8*z-12 = 0

23-8*z = 0

(23-8*z)/7 = 0

(23-8*z)/7 = 0 // * 7

23-8*z = 0

23-8*z = 0 // - 23

-8*z = -23 // : -8

z = -23/(-8)

z = 23/8

z = 23/8

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