3(2z-4)=-5(z+4)

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Solution for 3(2z-4)=-5(z+4) equation: 



3(2z-4)=-5(z+4)

We move all terms to the left:

3(2z-4)-(-5(z+4))=0

We multiply parentheses

6z-(-5(z+4))-12=0



We calculate terms in parentheses: -(-5(z+4)), so:

-5(z+4)

We multiply parentheses

-5z-20

Back to the equation:

-(-5z-20)



We get rid of parentheses

6z+5z+20-12=0

We add all the numbers together, and all the variables

11z+8=0

We move all terms containing z to the left, all other terms to the right

11z=-8

z=-8/11

z=-8/11

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