3(2z-4)=5(z+3)

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Solution for 3(2z-4)=5(z+3) equation:


Simplifying
3(2z + -4) = 5(z + 3)

Reorder the terms:
3(-4 + 2z) = 5(z + 3)
(-4 * 3 + 2z * 3) = 5(z + 3)
(-12 + 6z) = 5(z + 3)

Reorder the terms:
-12 + 6z = 5(3 + z)
-12 + 6z = (3 * 5 + z * 5)
-12 + 6z = (15 + 5z)

Solving
-12 + 6z = 15 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-12 + 6z + -5z = 15 + 5z + -5z

Combine like terms: 6z + -5z = 1z
-12 + 1z = 15 + 5z + -5z

Combine like terms: 5z + -5z = 0
-12 + 1z = 15 + 0
-12 + 1z = 15

Add '12' to each side of the equation.
-12 + 12 + 1z = 15 + 12

Combine like terms: -12 + 12 = 0
0 + 1z = 15 + 12
1z = 15 + 12

Combine like terms: 15 + 12 = 27
1z = 27

Divide each side by '1'.
z = 27

Simplifying
z = 27

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