3(2z-4)=5(z-4)

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Solution for 3(2z-4)=5(z-4) equation:


Simplifying
3(2z + -4) = 5(z + -4)

Reorder the terms:
3(-4 + 2z) = 5(z + -4)
(-4 * 3 + 2z * 3) = 5(z + -4)
(-12 + 6z) = 5(z + -4)

Reorder the terms:
-12 + 6z = 5(-4 + z)
-12 + 6z = (-4 * 5 + z * 5)
-12 + 6z = (-20 + 5z)

Solving
-12 + 6z = -20 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-12 + 6z + -5z = -20 + 5z + -5z

Combine like terms: 6z + -5z = 1z
-12 + 1z = -20 + 5z + -5z

Combine like terms: 5z + -5z = 0
-12 + 1z = -20 + 0
-12 + 1z = -20

Add '12' to each side of the equation.
-12 + 12 + 1z = -20 + 12

Combine like terms: -12 + 12 = 0
0 + 1z = -20 + 12
1z = -20 + 12

Combine like terms: -20 + 12 = -8
1z = -8

Divide each side by '1'.
z = -8

Simplifying
z = -8

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