3(2z-4+2)=5(-3z+2)

Solution for 3(2z-4+2)=5(-3z+2) equation:

Simplifying
3(2z + -4 + 2) = 5(-3z + 2)

Reorder the terms:
3(-4 + 2 + 2z) = 5(-3z + 2)

Combine like terms: -4 + 2 = -2
3(-2 + 2z) = 5(-3z + 2)
(-2 * 3 + 2z * 3) = 5(-3z + 2)
(-6 + 6z) = 5(-3z + 2)

Reorder the terms:
-6 + 6z = 5(2 + -3z)
-6 + 6z = (2 * 5 + -3z * 5)
-6 + 6z = (10 + -15z)

Solving
-6 + 6z = 10 + -15z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '15z' to each side of the equation.
-6 + 6z + 15z = 10 + -15z + 15z

Combine like terms: 6z + 15z = 21z
-6 + 21z = 10 + -15z + 15z

Combine like terms: -15z + 15z = 0
-6 + 21z = 10 + 0
-6 + 21z = 10

Add '6' to each side of the equation.
-6 + 6 + 21z = 10 + 6

Combine like terms: -6 + 6 = 0
0 + 21z = 10 + 6
21z = 10 + 6

Combine like terms: 10 + 6 = 16
21z = 16

Divide each side by '21'.
z = 0.7619047619

Simplifying
z = 0.7619047619