3(2z-5)-3(1-22)=12

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Solution for 3(2z-5)-3(1-22)=12 equation: 



3(2z-5)-3(1-22)=12

We move all terms to the left:

3(2z-5)-3(1-22)-(12)=0

determiningTheFunctionDomain
3(2z-5)-12-3(1-22)=0

We add all the numbers together, and all the variables

3(2z-5)-12-3(-21)=0

We add all the numbers together, and all the variables

3(2z-5)+51=0

We multiply parentheses

6z-15+51=0

We add all the numbers together, and all the variables

6z+36=0

We move all terms containing z to the left, all other terms to the right

6z=-36

z=-36/6

z=-6

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