3(2z-5)=4+11

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Solution for 3(2z-5)=4+11 equation: 



3(2z-5)=4+11

We move all terms to the left:

3(2z-5)-(4+11)=0

We add all the numbers together, and all the variables

3(2z-5)-15=0

We multiply parentheses

6z-15-15=0

We add all the numbers together, and all the variables

6z-30=0

We move all terms containing z to the left, all other terms to the right

6z=30

z=30/6

z=5

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