3(2z-5)=4z+11

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Solution for 3(2z-5)=4z+11 equation:


Simplifying
3(2z + -5) = 4z + 11

Reorder the terms:
3(-5 + 2z) = 4z + 11
(-5 * 3 + 2z * 3) = 4z + 11
(-15 + 6z) = 4z + 11

Reorder the terms:
-15 + 6z = 11 + 4z

Solving
-15 + 6z = 11 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-15 + 6z + -4z = 11 + 4z + -4z

Combine like terms: 6z + -4z = 2z
-15 + 2z = 11 + 4z + -4z

Combine like terms: 4z + -4z = 0
-15 + 2z = 11 + 0
-15 + 2z = 11

Add '15' to each side of the equation.
-15 + 15 + 2z = 11 + 15

Combine like terms: -15 + 15 = 0
0 + 2z = 11 + 15
2z = 11 + 15

Combine like terms: 11 + 15 = 26
2z = 26

Divide each side by '2'.
z = 13

Simplifying
z = 13

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