3(2z-5)=5(z+2)

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Solution for 3(2z-5)=5(z+2) equation:


Simplifying
3(2z + -5) = 5(z + 2)

Reorder the terms:
3(-5 + 2z) = 5(z + 2)
(-5 * 3 + 2z * 3) = 5(z + 2)
(-15 + 6z) = 5(z + 2)

Reorder the terms:
-15 + 6z = 5(2 + z)
-15 + 6z = (2 * 5 + z * 5)
-15 + 6z = (10 + 5z)

Solving
-15 + 6z = 10 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-15 + 6z + -5z = 10 + 5z + -5z

Combine like terms: 6z + -5z = 1z
-15 + 1z = 10 + 5z + -5z

Combine like terms: 5z + -5z = 0
-15 + 1z = 10 + 0
-15 + 1z = 10

Add '15' to each side of the equation.
-15 + 15 + 1z = 10 + 15

Combine like terms: -15 + 15 = 0
0 + 1z = 10 + 15
1z = 10 + 15

Combine like terms: 10 + 15 = 25
1z = 25

Divide each side by '1'.
z = 25

Simplifying
z = 25

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