3(2z-6)-4(3z+1)=5-2(7+1)

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Solution for 3(2z-6)-4(3z+1)=5-2(7+1) equation: 



3(2z-6)-4(3z+1)=5-2(7+1)

We move all terms to the left:

3(2z-6)-4(3z+1)-(5-2(7+1))=0

We add all the numbers together, and all the variables

3(2z-6)-4(3z+1)-(5-28)=0

We add all the numbers together, and all the variables

3(2z-6)-4(3z+1)+23=0

We multiply parentheses

6z-12z-18-4+23=0

We add all the numbers together, and all the variables

-6z+1=0

We move all terms containing z to the left, all other terms to the right

-6z=-1

z=-1/-6

z=1/6

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