3(2z-6)04(3z+1)=5-2(z+1)

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Solution for 3(2z-6)04(3z+1)=5-2(z+1) equation: 



3(2z-6)04(3z+1)=5-2(z+1)

We move all terms to the left:

3(2z-6)04(3z+1)-(5-2(z+1))=0



We calculate terms in parentheses: -(5-2(z+1)), so:

5-2(z+1)

determiningTheFunctionDomain
-2(z+1)+5

We multiply parentheses

-2z-2+5

We add all the numbers together, and all the variables

-2z+3

Back to the equation:

-(-2z+3)



We get rid of parentheses

3(2z-6)04(3z+1)+2z-3=0

We add all the numbers together, and all the variables

2z+3(2z-6)04(3z+1)-3=0

We move all terms containing z to the left, all other terms to the right

2z+3(2z-6)04(3z+1)=3

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