3(3(s-4))=4(2(s-3))

Solution for 3(3(s-4))=4(2(s-3)) equation:

Simplifying
3(3(s + -4)) = 4(2(s + -3))

Reorder the terms:
3(3(-4 + s)) = 4(2(s + -3))
3((-4 * 3 + s * 3)) = 4(2(s + -3))
3((-12 + 3s)) = 4(2(s + -3))
(-12 * 3 + 3s * 3) = 4(2(s + -3))
(-36 + 9s) = 4(2(s + -3))

Reorder the terms:
-36 + 9s = 4(2(-3 + s))
-36 + 9s = 4((-3 * 2 + s * 2))
-36 + 9s = 4((-6 + 2s))
-36 + 9s = (-6 * 4 + 2s * 4)
-36 + 9s = (-24 + 8s)

Solving
-36 + 9s = -24 + 8s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-8s' to each side of the equation.
-36 + 9s + -8s = -24 + 8s + -8s

Combine like terms: 9s + -8s = 1s
-36 + 1s = -24 + 8s + -8s

Combine like terms: 8s + -8s = 0
-36 + 1s = -24 + 0
-36 + 1s = -24

Add '36' to each side of the equation.
-36 + 36 + 1s = -24 + 36

Combine like terms: -36 + 36 = 0
0 + 1s = -24 + 36
1s = -24 + 36

Combine like terms: -24 + 36 = 12
1s = 12

Divide each side by '1'.
s = 12

Simplifying
s = 12