3(3+1)=2(3d-9)

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Solution for 3(3+1)=2(3d-9) equation: 



3(3+1)=2(3d-9)

We move all terms to the left:

3(3+1)-(2(3d-9))=0

We add all the numbers together, and all the variables

-(2(3d-9))+34=0



We calculate terms in parentheses: -(2(3d-9)), so:

2(3d-9)

We multiply parentheses

6d-18

Back to the equation:

-(6d-18)



We get rid of parentheses

-6d+18+34=0

We add all the numbers together, and all the variables

-6d+52=0

We move all terms containing d to the left, all other terms to the right

-6d=-52

d=-52/-6

d=8+2/3

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