3(3+2j)-3(j+2)=15

Solution for 3(3+2j)-3(j+2)=15 equation:

Simplifying
3(3 + 2j) + -3(j + 2) = 15
(3 * 3 + 2j * 3) + -3(j + 2) = 15
(9 + 6j) + -3(j + 2) = 15

Reorder the terms:
9 + 6j + -3(2 + j) = 15
9 + 6j + (2 * -3 + j * -3) = 15
9 + 6j + (-6 + -3j) = 15

Reorder the terms:
9 + -6 + 6j + -3j = 15

Combine like terms: 9 + -6 = 3
3 + 6j + -3j = 15

Combine like terms: 6j + -3j = 3j
3 + 3j = 15

Solving
3 + 3j = 15

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3j = 15 + -3

Combine like terms: 3 + -3 = 0
0 + 3j = 15 + -3
3j = 15 + -3

Combine like terms: 15 + -3 = 12
3j = 12

Divide each side by '3'.
j = 4

Simplifying
j = 4