3(3+2x)=(x+4)3

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Solution for 3(3+2x)=(x+4)3 equation: 



3(3+2x)=(x+4)3

We move all terms to the left:

3(3+2x)-((x+4)3)=0

We add all the numbers together, and all the variables

3(2x+3)-((x+4)3)=0

We multiply parentheses

6x-((x+4)3)+9=0



We calculate terms in parentheses: -((x+4)3), so:

(x+4)3

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

6x-3x-12+9=0

We add all the numbers together, and all the variables

3x-3=0

We move all terms containing x to the left, all other terms to the right

3x=3

x=3/3

x=1

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