3(3+2y)=-27-6y

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Solution for 3(3+2y)=-27-6y equation: 



3(3+2y)=-27-6y

We move all terms to the left:

3(3+2y)-(-27-6y)=0

We add all the numbers together, and all the variables

3(2y+3)-(-6y-27)=0

We multiply parentheses

6y-(-6y-27)+9=0

We get rid of parentheses

6y+6y+27+9=0

We add all the numbers together, and all the variables

12y+36=0

We move all terms containing y to the left, all other terms to the right

12y=-36

y=-36/12

y=-3

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