3(3+3x)-3=7x+18

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Solution for 3(3+3x)-3=7x+18 equation: 



3(3+3x)-3=7x+18

We move all terms to the left:

3(3+3x)-3-(7x+18)=0

We add all the numbers together, and all the variables

3(3x+3)-(7x+18)-3=0

We multiply parentheses

9x-(7x+18)+9-3=0

We get rid of parentheses

9x-7x-18+9-3=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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