3(3+c)=2(c-5)

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Solution for 3(3+c)=2(c-5) equation: 


Simplifying
3(3 + c) = 2(c + -5)
(3 * 3 + c * 3) = 2(c + -5)
(9 + 3c) = 2(c + -5)

Reorder the terms:
9 + 3c = 2(-5 + c)
9 + 3c = (-5 * 2 + c * 2)
9 + 3c = (-10 + 2c)

Solving
9 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
9 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
9 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
9 + 1c = -10 + 0
9 + 1c = -10

Add '-9' to each side of the equation.
9 + -9 + 1c = -10 + -9

Combine like terms: 9 + -9 = 0
0 + 1c = -10 + -9
1c = -10 + -9

Combine like terms: -10 + -9 = -19
1c = -19

Divide each side by '1'.
c = -19

Simplifying
c = -19

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