3(3+c)=2(c-6)

Solution for 3(3+c)=2(c-6) equation:

Simplifying
3(3 + c) = 2(c + -6)
(3 * 3 + c * 3) = 2(c + -6)
(9 + 3c) = 2(c + -6)

Reorder the terms:
9 + 3c = 2(-6 + c)
9 + 3c = (-6 * 2 + c * 2)
9 + 3c = (-12 + 2c)

Solving
9 + 3c = -12 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
9 + 3c + -2c = -12 + 2c + -2c

Combine like terms: 3c + -2c = 1c
9 + 1c = -12 + 2c + -2c

Combine like terms: 2c + -2c = 0
9 + 1c = -12 + 0
9 + 1c = -12

Add '-9' to each side of the equation.
9 + -9 + 1c = -12 + -9

Combine like terms: 9 + -9 = 0
0 + 1c = -12 + -9
1c = -12 + -9

Combine like terms: -12 + -9 = -21
1c = -21

Divide each side by '1'.
c = -21

Simplifying
c = -21