3(3+r)=(2r+4)

Solution for 3(3+r)=(2r+4) equation:

3(3+r)=(2r+4)

We move all terms to the left:

3(3+r)-((2r+4))=0

We add all the numbers together, and all the variables

3(r+3)-((2r+4))=0

We multiply parentheses

3r-((2r+4))+9=0


We calculate terms in parentheses: -((2r+4)), so:

(2r+4)

We get rid of parentheses

2r+4

Back to the equation:

-(2r+4)


We get rid of parentheses

3r-2r-4+9=0

We add all the numbers together, and all the variables

r+5=0

We move all terms containing r to the left, all other terms to the right

r=-5