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3(3+x-5)=(4)(4+x-8)
We move all terms to the left:
3(3+x-5)-((4)(4+x-8))=0
We add all the numbers together, and all the variables
3(x-2)-(4(x-4))=0
We multiply parentheses
3x-(4(x-4))-6=0
We calculate terms in parentheses: -(4(x-4)), so:We get rid of parentheses
4(x-4)
We multiply parentheses
4x-16
Back to the equation:
-(4x-16)
3x-4x+16-6=0
We add all the numbers together, and all the variables
-1x+10=0
We move all terms containing x to the left, all other terms to the right
-x=-10
x=-10/-1
x=+10
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