3(3+y)+1=31

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Solution for 3(3+y)+1=31 equation: 



3(3+y)+1=31

We move all terms to the left:

3(3+y)+1-(31)=0

We add all the numbers together, and all the variables

3(y+3)+1-31=0

We add all the numbers together, and all the variables

3(y+3)-30=0

We multiply parentheses

3y+9-30=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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