3(3-2b)-3(3b-6)=48

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Solution for 3(3-2b)-3(3b-6)=48 equation: 



3(3-2b)-3(3b-6)=48

We move all terms to the left:

3(3-2b)-3(3b-6)-(48)=0

We add all the numbers together, and all the variables

3(-2b+3)-3(3b-6)-48=0

We multiply parentheses

-6b-9b+9+18-48=0

We add all the numbers together, and all the variables

-15b-21=0

We move all terms containing b to the left, all other terms to the right

-15b=21

b=21/-15

b=-1+2/5

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