3(3-2x)=2(3x+1)

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Solution for 3(3-2x)=2(3x+1) equation: 



3(3-2x)=2(3x+1)

We move all terms to the left:

3(3-2x)-(2(3x+1))=0

We add all the numbers together, and all the variables

3(-2x+3)-(2(3x+1))=0

We multiply parentheses

-6x-(2(3x+1))+9=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-6x-6x-2+9=0

We add all the numbers together, and all the variables

-12x+7=0

We move all terms containing x to the left, all other terms to the right

-12x=-7

x=-7/-12

x=7/12

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