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3(3-2x)=2(4x+1)
We move all terms to the left:
3(3-2x)-(2(4x+1))=0
We add all the numbers together, and all the variables
3(-2x+3)-(2(4x+1))=0
We multiply parentheses
-6x-(2(4x+1))+9=0
We calculate terms in parentheses: -(2(4x+1)), so:We get rid of parentheses
2(4x+1)
We multiply parentheses
8x+2
Back to the equation:
-(8x+2)
-6x-8x-2+9=0
We add all the numbers together, and all the variables
-14x+7=0
We move all terms containing x to the left, all other terms to the right
-14x=-7
x=-7/-14
x=1/2
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