3(3-2x)=2(5x+1)

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Solution for 3(3-2x)=2(5x+1) equation: 



3(3-2x)=2(5x+1)

We move all terms to the left:

3(3-2x)-(2(5x+1))=0

We add all the numbers together, and all the variables

3(-2x+3)-(2(5x+1))=0

We multiply parentheses

-6x-(2(5x+1))+9=0



We calculate terms in parentheses: -(2(5x+1)), so:

2(5x+1)

We multiply parentheses

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

-6x-10x-2+9=0

We add all the numbers together, and all the variables

-16x+7=0

We move all terms containing x to the left, all other terms to the right

-16x=-7

x=-7/-16

x=7/16

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