3(3-2x)=3(2x+1)

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Solution for 3(3-2x)=3(2x+1) equation:



3(3-2x)=3(2x+1)
We move all terms to the left:
3(3-2x)-(3(2x+1))=0
We add all the numbers together, and all the variables
3(-2x+3)-(3(2x+1))=0
We multiply parentheses
-6x-(3(2x+1))+9=0
We calculate terms in parentheses: -(3(2x+1)), so:
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
We get rid of parentheses
-6x-6x-3+9=0
We add all the numbers together, and all the variables
-12x+6=0
We move all terms containing x to the left, all other terms to the right
-12x=-6
x=-6/-12
x=1/2

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