3(3-2x)=3(3x+1)

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Solution for 3(3-2x)=3(3x+1) equation: 



3(3-2x)=3(3x+1)

We move all terms to the left:

3(3-2x)-(3(3x+1))=0

We add all the numbers together, and all the variables

3(-2x+3)-(3(3x+1))=0

We multiply parentheses

-6x-(3(3x+1))+9=0



We calculate terms in parentheses: -(3(3x+1)), so:

3(3x+1)

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

-6x-9x-3+9=0

We add all the numbers together, and all the variables

-15x+6=0

We move all terms containing x to the left, all other terms to the right

-15x=-6

x=-6/-15

x=2/5

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