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3(3-2x)=3(5x+1)
We move all terms to the left:
3(3-2x)-(3(5x+1))=0
We add all the numbers together, and all the variables
3(-2x+3)-(3(5x+1))=0
We multiply parentheses
-6x-(3(5x+1))+9=0
We calculate terms in parentheses: -(3(5x+1)), so:We get rid of parentheses
3(5x+1)
We multiply parentheses
15x+3
Back to the equation:
-(15x+3)
-6x-15x-3+9=0
We add all the numbers together, and all the variables
-21x+6=0
We move all terms containing x to the left, all other terms to the right
-21x=-6
x=-6/-21
x=2/7
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