3(3-2x)=30-2x+3

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Solution for 3(3-2x)=30-2x+3 equation: 



3(3-2x)=30-2x+3

We move all terms to the left:

3(3-2x)-(30-2x+3)=0

We add all the numbers together, and all the variables

3(-2x+3)-(-2x+33)=0

We multiply parentheses

-6x-(-2x+33)+9=0

We get rid of parentheses

-6x+2x-33+9=0

We add all the numbers together, and all the variables

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6

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