3(3-3i)=2(i+3)-30

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Solution for 3(3-3i)=2(i+3)-30 equation: 



3(3-3i)=2(i+3)-30

We move all terms to the left:

3(3-3i)-(2(i+3)-30)=0

We add all the numbers together, and all the variables

3(-3i+3)-(2(i+3)-30)=0

We multiply parentheses

-9i-(2(i+3)-30)+9=0



We calculate terms in parentheses: -(2(i+3)-30), so:

2(i+3)-30

We multiply parentheses

2i+6-30

We add all the numbers together, and all the variables

2i-24

Back to the equation:

-(2i-24)



We get rid of parentheses

-9i-2i+24+9=0

We add all the numbers together, and all the variables

-11i+33=0

We move all terms containing i to the left, all other terms to the right

-11i=-33

i=-33/-11

i=+3

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