3(3-3r)=2(r+3)-30

Solution for 3(3-3r)=2(r+3)-30 equation:

3(3-3r)=2(r+3)-30

We move all terms to the left:

3(3-3r)-(2(r+3)-30)=0

We add all the numbers together, and all the variables

3(-3r+3)-(2(r+3)-30)=0

We multiply parentheses

-9r-(2(r+3)-30)+9=0


We calculate terms in parentheses: -(2(r+3)-30), so:

2(r+3)-30

We multiply parentheses

2r+6-30

We add all the numbers together, and all the variables

2r-24

Back to the equation:

-(2r-24)


We get rid of parentheses

-9r-2r+24+9=0

We add all the numbers together, and all the variables

-11r+33=0

We move all terms containing r to the left, all other terms to the right

-11r=-33

r=-33/-11

r=+3