3(3-3x)=2(x+2)-30

Solution for 3(3-3x)=2(x+2)-30 equation:

3(3-3x)=2(x+2)-30

We move all terms to the left:

3(3-3x)-(2(x+2)-30)=0

We add all the numbers together, and all the variables

3(-3x+3)-(2(x+2)-30)=0

We multiply parentheses

-9x-(2(x+2)-30)+9=0


We calculate terms in parentheses: -(2(x+2)-30), so:

2(x+2)-30

We multiply parentheses

2x+4-30

We add all the numbers together, and all the variables

2x-26

Back to the equation:

-(2x-26)


We get rid of parentheses

-9x-2x+26+9=0

We add all the numbers together, and all the variables

-11x+35=0

We move all terms containing x to the left, all other terms to the right

-11x=-35

x=-35/-11

x=3+2/11