3(3-3x)=2(x+3)-30

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Solution for 3(3-3x)=2(x+3)-30 equation: 



3(3-3x)=2(x+3)-30

We move all terms to the left:

3(3-3x)-(2(x+3)-30)=0

We add all the numbers together, and all the variables

3(-3x+3)-(2(x+3)-30)=0

We multiply parentheses

-9x-(2(x+3)-30)+9=0



We calculate terms in parentheses: -(2(x+3)-30), so:

2(x+3)-30

We multiply parentheses

2x+6-30

We add all the numbers together, and all the variables

2x-24

Back to the equation:

-(2x-24)



We get rid of parentheses

-9x-2x+24+9=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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