3(3-3x)=2(x+3)-30.

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Solution for 3(3-3x)=2(x+3)-30. equation:



3(3-3x)=2(x+3)-30.
We move all terms to the left:
3(3-3x)-(2(x+3)-30.)=0
We add all the numbers together, and all the variables
3(-3x+3)-(2(x+3)-30.)=0
We multiply parentheses
-9x-(2(x+3)-30.)+9=0
We calculate terms in parentheses: -(2(x+3)-30.), so:
2(x+3)-30.
We add all the numbers together, and all the variables
2(x+3)-30
We multiply parentheses
2x+6-30
We add all the numbers together, and all the variables
2x-24
Back to the equation:
-(2x-24)
We get rid of parentheses
-9x-2x+24+9=0
We add all the numbers together, and all the variables
-11x+33=0
We move all terms containing x to the left, all other terms to the right
-11x=-33
x=-33/-11
x=+3

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