3(3-4a)+4a=41

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Solution for 3(3-4a)+4a=41 equation: 



3(3-4a)+4a=41

We move all terms to the left:

3(3-4a)+4a-(41)=0

We add all the numbers together, and all the variables

3(-4a+3)+4a-41=0

We add all the numbers together, and all the variables

4a+3(-4a+3)-41=0

We multiply parentheses

4a-12a+9-41=0

We add all the numbers together, and all the variables

-8a-32=0

We move all terms containing a to the left, all other terms to the right

-8a=32

a=32/-8

a=-4

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